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150153142441 = 251598219691
BaseRepresentation
bin1000101111010111010…
…0110010000010101001
3112100120102121221210211
42023311310302002221
54430003201024231
6152551314541121
713563635436451
oct2136564620251
9470512557724
10150153142441
1158752597355
1225125b977a1
131120c20b7a3
1473a5c56d61
153d8c27eeb1
hex22f5d320a9

150153142441 has 4 divisors (see below), whose sum is σ = 150751362384. Its totient is φ = 149554922500.

The previous prime is 150153142429. The next prime is 150153142457. The reversal of 150153142441 is 144241351051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150153142441 - 223 = 150144753833 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150153142241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 299109595 + ... + 299110096.

It is an arithmetic number, because the mean of its divisors is an integer number (37687840596).

Almost surely, 2150153142441 is an apocalyptic number.

It is an amenable number.

150153142441 is a deficient number, since it is larger than the sum of its proper divisors (598219943).

150153142441 is an equidigital number, since it uses as much as digits as its factorization.

150153142441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 598219942.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 150153142441 its reverse (144241351051), we get a palindrome (294394493492).

The spelling of 150153142441 in words is "one hundred fifty billion, one hundred fifty-three million, one hundred forty-two thousand, four hundred forty-one".

Divisors: 1 251 598219691 150153142441