Base | Representation |
---|---|
bin | 100010001001101111110111… |
… | …000000101010100100001001 |
3 | 201200211022100100222201210121 |
4 | 202021233313000222210021 |
5 | 124141413124014030423 |
6 | 1251242302114143241 |
7 | 43431561254453131 |
oct | 4211576700524411 |
9 | 650738310881717 |
10 | 150203445455113 |
11 | 4394aa18188926 |
12 | 14a1a525b81b21 |
13 | 65a717c93770b |
14 | 2913c57d3bac1 |
15 | 125720a0d945d |
hex | 889bf702a909 |
150203445455113 has 4 divisors (see below), whose sum is σ = 151891124617620. Its totient is φ = 148515766292608.
The previous prime is 150203445455099. The next prime is 150203445455243. The reversal of 150203445455113 is 311554544302051.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 106140826286089 + 44062619169024 = 10302467^2 + 6637968^2 .
It is a cyclic number.
It is not a de Polignac number, because 150203445455113 - 25 = 150203445455081 is a prime.
It is a super-2 number, since 2×1502034454551132 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 150203445455113.
It is not an unprimeable number, because it can be changed into a prime (150203445455813) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 843839581120 + ... + 843839581297.
It is an arithmetic number, because the mean of its divisors is an integer number (37972781154405).
Almost surely, 2150203445455113 is an apocalyptic number.
It is an amenable number.
150203445455113 is a deficient number, since it is larger than the sum of its proper divisors (1687679162507).
150203445455113 is an equidigital number, since it uses as much as digits as its factorization.
150203445455113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1687679162506.
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 150203445455113 its reverse (311554544302051), we get a palindrome (461757989757164).
The spelling of 150203445455113 in words is "one hundred fifty trillion, two hundred three billion, four hundred forty-five million, four hundred fifty-five thousand, one hundred thirteen".
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