Base | Representation |
---|---|
bin | 1000101111111101001… |
… | …0111011101011000001 |
3 | 112100222111121211212022 |
4 | 2023333102323223001 |
5 | 4430314340304103 |
6 | 153015152411225 |
7 | 13600605161141 |
oct | 2137722735301 |
9 | 470874554768 |
10 | 150312041153 |
11 | 588242572aa |
12 | 2516b246b15 |
13 | 11236104bb1 |
14 | 73bcdba921 |
15 | 3d9b1bb138 |
hex | 22ff4bbac1 |
150312041153 has 4 divisors (see below), whose sum is σ = 150313039920. Its totient is φ = 150311042388.
The previous prime is 150312041137. The next prime is 150312041179. The reversal of 150312041153 is 351140213051.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 150312041153 - 24 = 150312041137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (150312041183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222443 + ... + 591696.
It is an arithmetic number, because the mean of its divisors is an integer number (37578259980).
Almost surely, 2150312041153 is an apocalyptic number.
It is an amenable number.
150312041153 is a deficient number, since it is larger than the sum of its proper divisors (998767).
150312041153 is an equidigital number, since it uses as much as digits as its factorization.
150312041153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 998766.
The product of its (nonzero) digits is 1800, while the sum is 26.
The spelling of 150312041153 in words is "one hundred fifty billion, three hundred twelve million, forty-one thousand, one hundred fifty-three".
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