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150335256113 = 758813651839
BaseRepresentation
bin1000110000000010101…
…1011111011000110001
3112101001010022021210122
42030000223133120301
54430341311143423
6153021342140025
713601306410220
oct2140053373061
9471033267718
10150335256113
1158836373019
1225176b81615
131123ab72763
1473c2100cb7
153d9d2548c8
hex2300adf631

150335256113 has 8 divisors (see below), whose sum is σ = 171840983040. Its totient is φ = 128836844640.

The previous prime is 150335256107. The next prime is 150335256193. The reversal of 150335256113 is 311652533051.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 150335256113 - 232 = 146040288817 is a prime.

It is a super-2 number, since 2×1503352561132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150335256193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1784753 + ... + 1867086.

It is an arithmetic number, because the mean of its divisors is an integer number (21480122880).

Almost surely, 2150335256113 is an apocalyptic number.

It is an amenable number.

150335256113 is a deficient number, since it is larger than the sum of its proper divisors (21505726927).

150335256113 is an equidigital number, since it uses as much as digits as its factorization.

150335256113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3657727.

The product of its (nonzero) digits is 40500, while the sum is 35.

Adding to 150335256113 its reverse (311652533051), we get a palindrome (461987789164).

The spelling of 150335256113 in words is "one hundred fifty billion, three hundred thirty-five million, two hundred fifty-six thousand, one hundred thirteen".

Divisors: 1 7 5881 41167 3651839 25562873 21476465159 150335256113