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150343412401115 = 530068682480223
BaseRepresentation
bin100010001011110010001101…
…101100001100001111011011
3201201022200121220111021222122
4202023302031230030033123
5124201211302033313430
61251430450555411455
743444644625044113
oct4213621554141733
9651280556437878
10150343412401115
11439a431294600a
1214a41688753b8b
1365b74276c561b
14291a935004043
15125ab9ce7bee5
hex88bc8db0c3db

150343412401115 has 4 divisors (see below), whose sum is σ = 180412094881344. Its totient is φ = 120274729920888.

The previous prime is 150343412401109. The next prime is 150343412401151. The reversal of 150343412401115 is 511104214343051.

150343412401115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 150343412401115 - 222 = 150343408206811 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15034341240107 + ... + 15034341240116.

It is an arithmetic number, because the mean of its divisors is an integer number (45103023720336).

Almost surely, 2150343412401115 is an apocalyptic number.

150343412401115 is a deficient number, since it is larger than the sum of its proper divisors (30068682480229).

150343412401115 is an equidigital number, since it uses as much as digits as its factorization.

150343412401115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30068682480228.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 150343412401115 its reverse (511104214343051), we get a palindrome (661447626744166).

The spelling of 150343412401115 in words is "one hundred fifty trillion, three hundred forty-three billion, four hundred twelve million, four hundred one thousand, one hundred fifteen".

Divisors: 1 5 30068682480223 150343412401115