Search a number
-
+
15040105313 = 43444778653
BaseRepresentation
bin11100000000111010…
…11100101101100001
31102211011121111211112
432000131130231201
5221300231332223
610524225353105
71041464533352
oct160035345541
942734544745
1015040105313
116418824802
122ab8a98795
131558c4b7cc
14a296a3d29
155d05d7778
hex38075cb61

15040105313 has 8 divisors (see below), whose sum is σ = 15393531648. Its totient is φ = 14686845264.

The previous prime is 15040105303. The next prime is 15040105349. The reversal of 15040105313 is 31350104051.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 15040105313 - 220 = 15039056737 is a prime.

It is a super-2 number, since 2×150401053132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15040105303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 151895 + ... + 230547.

It is an arithmetic number, because the mean of its divisors is an integer number (1924191456).

Almost surely, 215040105313 is an apocalyptic number.

It is an amenable number.

15040105313 is a deficient number, since it is larger than the sum of its proper divisors (353426335).

15040105313 is an equidigital number, since it uses as much as digits as its factorization.

15040105313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83143.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 15040105313 its reverse (31350104051), we get a palindrome (46390209364).

The spelling of 15040105313 in words is "fifteen billion, forty million, one hundred five thousand, three hundred thirteen".

Divisors: 1 43 4447 78653 191221 3382079 349769891 15040105313