Search a number
-
+
15040113 = 311455761
BaseRepresentation
bin111001010111…
…111001110001
31001022010011020
4321113321301
512322240423
61254210053
7241560504
oct71277161
931263136
1015040113
118542950
125053929
13316799a
141dd713b
1514c14e3
hexe57e71

15040113 has 8 divisors (see below), whose sum is σ = 21876576. Its totient is φ = 9115200.

The previous prime is 15040111. The next prime is 15040127. The reversal of 15040113 is 31104051.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 15040113 - 21 = 15040111 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 15040092 and 15040101.

It is not an unprimeable number, because it can be changed into a prime (15040111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 227848 + ... + 227913.

It is an arithmetic number, because the mean of its divisors is an integer number (2734572).

Almost surely, 215040113 is an apocalyptic number.

It is an amenable number.

15040113 is a deficient number, since it is larger than the sum of its proper divisors (6836463).

15040113 is a wasteful number, since it uses less digits than its factorization.

15040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 455775.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 15040113 is about 3878.1584547308. The cubic root of 15040113 is about 246.8408499042.

Adding to 15040113 its reverse (31104051), we get a palindrome (46144164).

The spelling of 15040113 in words is "fifteen million, forty thousand, one hundred thirteen".

Divisors: 1 3 11 33 455761 1367283 5013371 15040113