Base | Representation |
---|---|
bin | 100010001100101000001110… |
… | …000110000111000001111011 |
3 | 201201112020022020202020120002 |
4 | 202030220032012013001323 |
5 | 124203134032210112021 |
6 | 1251513241102023215 |
7 | 43452066634132145 |
oct | 4214501606070173 |
9 | 651466266666502 |
10 | 150401401254011 |
11 | 43a16970062526 |
12 | 14a50970b77b0b |
13 | 65bca395a472b |
14 | 291d676739c95 |
15 | 125c443d6950b |
hex | 88ca0e18707b |
150401401254011 has 4 divisors (see below), whose sum is σ = 150423646698024. Its totient is φ = 150379155810000.
The previous prime is 150401401253903. The next prime is 150401401254037. The reversal of 150401401254011 is 110452104104051.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 150401401254011 - 218 = 150401400991867 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (150401401254911) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11122711865 + ... + 11122725386.
It is an arithmetic number, because the mean of its divisors is an integer number (37605911674506).
Almost surely, 2150401401254011 is an apocalyptic number.
150401401254011 is a deficient number, since it is larger than the sum of its proper divisors (22245444013).
150401401254011 is an equidigital number, since it uses as much as digits as its factorization.
150401401254011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22245444012.
The product of its (nonzero) digits is 3200, while the sum is 29.
Adding to 150401401254011 its reverse (110452104104051), we get a palindrome (260853505358062).
The spelling of 150401401254011 in words is "one hundred fifty trillion, four hundred one billion, four hundred one million, two hundred fifty-four thousand, eleven".
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