Search a number
-
+
150415430411 = 374065281903
BaseRepresentation
bin1000110000010101110…
…1010101001100001011
3112101020201011120021002
42030011131111030023
54431022322233121
6153033324405215
713603302030431
oct2140535251413
9471221146232
10150415430411
1158877653174
12251999a680b
131125166427c
1473cca10d51
153da52dee0b
hex230575530b

150415430411 has 4 divisors (see below), whose sum is σ = 154480712352. Its totient is φ = 146350148472.

The previous prime is 150415430377. The next prime is 150415430441. The reversal of 150415430411 is 114034514051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150415430411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150415430441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2032640915 + ... + 2032640988.

It is an arithmetic number, because the mean of its divisors is an integer number (38620178088).

Almost surely, 2150415430411 is an apocalyptic number.

150415430411 is a deficient number, since it is larger than the sum of its proper divisors (4065281941).

150415430411 is an equidigital number, since it uses as much as digits as its factorization.

150415430411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4065281940.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 150415430411 its reverse (114034514051), we get a palindrome (264449944462).

The spelling of 150415430411 in words is "one hundred fifty billion, four hundred fifteen million, four hundred thirty thousand, four hundred eleven".

Divisors: 1 37 4065281903 150415430411