Base | Representation |
---|---|
bin | 1101101011100100101101… |
… | …1111100010111100101011 |
3 | 1222021000122201011220122011 |
4 | 3122321023133202330223 |
5 | 3432423002430001103 |
6 | 51554151030540351 |
7 | 3111523531425106 |
oct | 332711337427453 |
9 | 58230581156564 |
10 | 15042242031403 |
11 | 487a419526a34 |
12 | 182b3545076b7 |
13 | 85162892ba32 |
14 | 3a0096b4173d |
15 | 1b143adbbd6d |
hex | dae4b7e2f2b |
15042242031403 has 4 divisors (see below), whose sum is σ = 15042294107568. Its totient is φ = 15042189955240.
The previous prime is 15042242031391. The next prime is 15042242031473. The reversal of 15042242031403 is 30413024224051.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 15042242031403 - 229 = 15041705160491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15042242031473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25602376 + ... + 26183317.
It is an arithmetic number, because the mean of its divisors is an integer number (3760573526892).
Almost surely, 215042242031403 is an apocalyptic number.
15042242031403 is a deficient number, since it is larger than the sum of its proper divisors (52076165).
15042242031403 is an equidigital number, since it uses as much as digits as its factorization.
15042242031403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52076164.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 15042242031403 its reverse (30413024224051), we get a palindrome (45455266255454).
The spelling of 15042242031403 in words is "fifteen trillion, forty-two billion, two hundred forty-two million, thirty-one thousand, four hundred three".
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