Base | Representation |
---|---|
bin | 1101101100001101010000… |
… | …0111000100111010100001 |
3 | 1222022001202002120201112102 |
4 | 3123003110013010322201 |
5 | 3433112244222430423 |
6 | 52003150521540145 |
7 | 3112360306042631 |
oct | 333032407047241 |
9 | 58261662521472 |
10 | 15053124030113 |
11 | 4883aa30986a4 |
12 | 1831490944655 |
13 | 85267127c120 |
14 | 3a080a0966c1 |
15 | 1b18763ecc28 |
hex | db0d41c4ea1 |
15053124030113 has 8 divisors (see below), whose sum is σ = 16222002689256. Its totient is φ = 13885809091200.
The previous prime is 15053124030089. The next prime is 15053124030137. The reversal of 15053124030113 is 31103042135051.
It is an interprime number because it is at equal distance from previous prime (15053124030089) and next prime (15053124030137).
It can be written as a sum of positive squares in 4 ways, for example, as 4372780129 + 15048751249984 = 66127^2 + 3879272^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 15053124030113 - 214 = 15053124013729 is a prime.
It is not an unprimeable number, because it can be changed into a prime (15053124020113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 390910058 + ... + 390948563.
It is an arithmetic number, because the mean of its divisors is an integer number (2027750336157).
Almost surely, 215053124030113 is an apocalyptic number.
15053124030113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
15053124030113 is a deficient number, since it is larger than the sum of its proper divisors (1168878659143).
15053124030113 is a wasteful number, since it uses less digits than its factorization.
15053124030113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 781860115.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 15053124030113 its reverse (31103042135051), we get a palindrome (46156166165164).
The spelling of 15053124030113 in words is "fifteen trillion, fifty-three billion, one hundred twenty-four million, thirty thousand, one hundred thirteen".
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