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150532463121 = 350177487707
BaseRepresentation
bin1000110000110001101…
…1110001101000010001
3112101112212101102221220
42030030123301220101
54431242302304441
6153053105035253
713606222552605
oct2141433615021
9471485342856
10150532463121
1158927718617
1225211025b29
131126c98c6b1
147400397505
153db070b466
hex230c6f1a11

150532463121 has 4 divisors (see below), whose sum is σ = 200709950832. Its totient is φ = 100354975412.

The previous prime is 150532463119. The next prime is 150532463153. The reversal of 150532463121 is 121364235051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150532463121 - 21 = 150532463119 is a prime.

It is not an unprimeable number, because it can be changed into a prime (150532463101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25088743851 + ... + 25088743856.

It is an arithmetic number, because the mean of its divisors is an integer number (50177487708).

Almost surely, 2150532463121 is an apocalyptic number.

It is an amenable number.

150532463121 is a deficient number, since it is larger than the sum of its proper divisors (50177487711).

150532463121 is an equidigital number, since it uses as much as digits as its factorization.

150532463121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50177487710.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 150532463121 its reverse (121364235051), we get a palindrome (271896698172).

The spelling of 150532463121 in words is "one hundred fifty billion, five hundred thirty-two million, four hundred sixty-three thousand, one hundred twenty-one".

Divisors: 1 3 50177487707 150532463121