Base | Representation |
---|---|
bin | 1000110000110110001… |
… | …0111111000101000001 |
3 | 112101121011111211200211 |
4 | 2030031202333011001 |
5 | 4431312042133213 |
6 | 153055013114121 |
7 | 13606540331344 |
oct | 2141542770501 |
9 | 471534454624 |
10 | 150551130433 |
11 | 58937208650 |
12 | 25217328941 |
13 | 112737c7342 |
14 | 7402a5645b |
15 | 3db219753d |
hex | 230d8bf141 |
150551130433 has 16 divisors (see below), whose sum is σ = 183051195840. Its totient is φ = 122034124800.
The previous prime is 150551130409. The next prime is 150551130437. The reversal of 150551130433 is 334031155051.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-150551130433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 150551130395 and 150551130404.
It is not an unprimeable number, because it can be changed into a prime (150551130437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21182928 + ... + 21190033.
It is an arithmetic number, because the mean of its divisors is an integer number (11440699740).
Almost surely, 2150551130433 is an apocalyptic number.
It is an amenable number.
150551130433 is a deficient number, since it is larger than the sum of its proper divisors (32500065407).
150551130433 is a wasteful number, since it uses less digits than its factorization.
150551130433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42373008.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 150551130433 its reverse (334031155051), we get a palindrome (484582285484).
The spelling of 150551130433 in words is "one hundred fifty billion, five hundred fifty-one million, one hundred thirty thousand, four hundred thirty-three".
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