Base | Representation |
---|---|
bin | 1101101100010100110001… |
… | …1001001011110101111011 |
3 | 1222022020221201211101210120 |
4 | 3123011030121023311323 |
5 | 3433130412330334003 |
6 | 52004123050544323 |
7 | 3112461311626266 |
oct | 333051431136573 |
9 | 58266851741716 |
10 | 15055142043003 |
11 | 4884939218647 |
12 | 18319547380a3 |
13 | 8529033922aa |
14 | 3a095c0bdcdd |
15 | 1b194366c853 |
hex | db14c64bd7b |
15055142043003 has 4 divisors (see below), whose sum is σ = 20073522724008. Its totient is φ = 10036761362000.
The previous prime is 15055142042957. The next prime is 15055142043077. The reversal of 15055142043003 is 30034024155051.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 15055142043003 - 28 = 15055142042747 is a prime.
It is not an unprimeable number, because it can be changed into a prime (15055142043803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2509190340498 + ... + 2509190340503.
It is an arithmetic number, because the mean of its divisors is an integer number (5018380681002).
Almost surely, 215055142043003 is an apocalyptic number.
15055142043003 is a deficient number, since it is larger than the sum of its proper divisors (5018380681005).
15055142043003 is an equidigital number, since it uses as much as digits as its factorization.
15055142043003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5018380681004.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 15055142043003 its reverse (30034024155051), we get a palindrome (45089166198054).
The spelling of 15055142043003 in words is "fifteen trillion, fifty-five billion, one hundred forty-two million, forty-three thousand, three".
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