Base | Representation |
---|---|
bin | 100010001110110100000001… |
… | …111111010111000011011011 |
3 | 201202001120210102102222011201 |
4 | 202032310001333113003123 |
5 | 124213114004113412103 |
6 | 1252110225302535031 |
7 | 43465663030416460 |
oct | 4216640177270333 |
9 | 652046712388151 |
10 | 150551522013403 |
11 | 43a745a6340a25 |
12 | 14a75a88137477 |
13 | 6600c41b85644 |
14 | 2926a38163667 |
15 | 12612cd34e51d |
hex | 88ed01fd70db |
150551522013403 has 8 divisors (see below), whose sum is σ = 172093932020960. Its totient is φ = 129017874435840.
The previous prime is 150551522013377. The next prime is 150551522013421. The reversal of 150551522013403 is 304310225155051.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 150551522013403 - 217 = 150551521882331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (150551522016403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2190570678 + ... + 2190639403.
It is an arithmetic number, because the mean of its divisors is an integer number (21511741502620).
Almost surely, 2150551522013403 is an apocalyptic number.
150551522013403 is a deficient number, since it is larger than the sum of its proper divisors (21542410007557).
150551522013403 is an equidigital number, since it uses as much as digits as its factorization.
150551522013403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4381214997.
The product of its (nonzero) digits is 90000, while the sum is 37.
Adding to 150551522013403 its reverse (304310225155051), we get a palindrome (454861747168454).
The spelling of 150551522013403 in words is "one hundred fifty trillion, five hundred fifty-one billion, five hundred twenty-two million, thirteen thousand, four hundred three".
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