151034131 has 4 divisors (see below), whose sum is σ = 151058992. Its totient is φ = 151009272.

The previous prime is 151034129. The next prime is 151034161. The reversal of 151034131 is 131430151.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 131430151 = 3067 ⋅42853.

It is a cyclic number.

It is not a de Polignac number, because 151034131 - 2¹ = 151034129 is a prime.

It is a super-2 number, since 2×151034131² = 45622617453850322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 151034099 and 151034108.

It is not an unprimeable number, because it can be changed into a prime (151034101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3421 + ... + 17713.

It is an arithmetic number, because the mean of its divisors is an integer number (37764748).

Almost surely, 2^151034131 is an apocalyptic number.

151034131 is a deficient number, since it is larger than the sum of its proper divisors (24861).

151034131 is a wasteful number, since it uses less digits than its factorization.

151034131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24860.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 151034131 is about 12289.5944196707. The cubic root of 151034131 is about 532.5475205741.

Adding to 151034131 its reverse (131430151), we get a palindrome (282464282).

The spelling of 151034131 in words is "one hundred fifty-one million, thirty-four thousand, one hundred thirty-one".