Base | Representation |
---|---|
bin | 100010010111001111110101… |
… | …111111000101110111000001 |
3 | 201211002222220002012111110220 |
4 | 202113033311333011313001 |
5 | 124302113034121420340 |
6 | 1253232404321413253 |
7 | 43555602365263404 |
oct | 4227176577056701 |
9 | 654088802174426 |
10 | 151131141201345 |
11 | 441783a2255798 |
12 | 14b4a28949a229 |
13 | 66437b4284536 |
14 | 2946b01713d3b |
15 | 1271403ccced0 |
hex | 8973f5fc5dc1 |
151131141201345 has 16 divisors (see below), whose sum is σ = 244028264694720. Its totient is φ = 79863795716544.
The previous prime is 151131141201289. The next prime is 151131141201377. The reversal of 151131141201345 is 543102141131151.
It is not a de Polignac number, because 151131141201345 - 27 = 151131141201217 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46217472739 + ... + 46217476008.
It is an arithmetic number, because the mean of its divisors is an integer number (15251766543420).
Almost surely, 2151131141201345 is an apocalyptic number.
151131141201345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
151131141201345 is a deficient number, since it is larger than the sum of its proper divisors (92897123493375).
151131141201345 is a wasteful number, since it uses less digits than its factorization.
151131141201345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92434948864.
The product of its (nonzero) digits is 7200, while the sum is 33.
Adding to 151131141201345 its reverse (543102141131151), we get a palindrome (694233282332496).
The spelling of 151131141201345 in words is "one hundred fifty-one trillion, one hundred thirty-one billion, one hundred forty-one million, two hundred one thousand, three hundred forty-five".
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