Base | Representation |
---|---|
bin | 100010010111010000001011… |
… | …011001110101110101001011 |
3 | 201211010000211010100112202001 |
4 | 202113100023121311311023 |
5 | 124302114303114110430 |
6 | 1253232504115251431 |
7 | 43555614320463622 |
oct | 4227201331656513 |
9 | 654100733315661 |
10 | 151131500535115 |
11 | 44178567075551 |
12 | 14b4a3698a9b77 |
13 | 6643840857c79 |
14 | 2946b373306b9 |
15 | 127142560c3ca |
hex | 89740b675d4b |
151131500535115 has 16 divisors (see below), whose sum is σ = 188070225847200. Its totient is φ = 116450637311232.
The previous prime is 151131500535091. The next prime is 151131500535137. The reversal of 151131500535115 is 511535005131151.
151131500535115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 151131500535115 - 215 = 151131500502347 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1274129217 + ... + 1274247826.
It is an arithmetic number, because the mean of its divisors is an integer number (11754389115450).
Almost surely, 2151131500535115 is an apocalyptic number.
151131500535115 is a deficient number, since it is larger than the sum of its proper divisors (36938725312085).
151131500535115 is a wasteful number, since it uses less digits than its factorization.
151131500535115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2548377486.
The product of its (nonzero) digits is 28125, while the sum is 37.
Adding to 151131500535115 its reverse (511535005131151), we get a palindrome (662666505666266).
The spelling of 151131500535115 in words is "one hundred fifty-one trillion, one hundred thirty-one billion, five hundred million, five hundred thirty-five thousand, one hundred fifteen".
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