Base | Representation |
---|---|
bin | 1000110011000000110… |
… | …0000000101000100011 |
3 | 112110002200002211020212 |
4 | 2030300030000220203 |
5 | 4434004332410201 |
6 | 153232413524335 |
7 | 13630125303512 |
oct | 2146014005043 |
9 | 473080084225 |
10 | 151132310051 |
11 | 59105281488 |
12 | 25359aa36ab |
13 | 113370336c8 |
14 | 7459d00679 |
15 | 3de81e8abb |
hex | 2330300a23 |
151132310051 has 4 divisors (see below), whose sum is σ = 151133869704. Its totient is φ = 151130750400.
The previous prime is 151132310039. The next prime is 151132310059. The reversal of 151132310051 is 150013231151.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 151132310051 - 230 = 150058568227 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 151132309999 and 151132310026.
It is not an unprimeable number, because it can be changed into a prime (151132310059) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 624110 + ... + 831731.
It is an arithmetic number, because the mean of its divisors is an integer number (37783467426).
Almost surely, 2151132310051 is an apocalyptic number.
151132310051 is a deficient number, since it is larger than the sum of its proper divisors (1559653).
151132310051 is a wasteful number, since it uses less digits than its factorization.
151132310051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1559652.
The product of its (nonzero) digits is 450, while the sum is 23.
The spelling of 151132310051 in words is "one hundred fifty-one billion, one hundred thirty-two million, three hundred ten thousand, fifty-one".
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