1511341113 has 4 divisors (see below), whose sum is σ = 2015121488. Its totient is φ = 1007560740.

The previous prime is 1511341103. The next prime is 1511341127. The reversal of 1511341113 is 3111431151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3111431151 = 3 ⋅1037143717.

It is not a de Polignac number, because 1511341113 - 2⁶ = 1511341049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1511341113.

It is not an unprimeable number, because it can be changed into a prime (1511341103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251890183 + ... + 251890188.

It is an arithmetic number, because the mean of its divisors is an integer number (503780372).

Almost surely, 2^1511341113 is an apocalyptic number.

It is an amenable number.

1511341113 is a deficient number, since it is larger than the sum of its proper divisors (503780375).

1511341113 is an equidigital number, since it uses as much as digits as its factorization.

1511341113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 503780374.

The product of its digits is 180, while the sum is 21.

The square root of 1511341113 is about 38875.9708946285. The cubic root of 1511341113 is about 1147.5919651376.

Adding to 1511341113 its reverse (3111431151), we get a palindrome (4622772264).

The spelling of 1511341113 in words is "one billion, five hundred eleven million, three hundred forty-one thousand, one hundred thirteen".