Base | Representation |
---|---|
bin | 100010010111011010111010… |
… | …100011111000001111010011 |
3 | 201211011010120120102000122012 |
4 | 202113122322203320033103 |
5 | 124302311410423120221 |
6 | 1253242052104533135 |
7 | 43556503106002340 |
oct | 4227327243701723 |
9 | 654133516360565 |
10 | 151143029113811 |
11 | 4418244270a339 |
12 | 14b506467811ab |
13 | 664495a132777 |
14 | 294750c4b57c7 |
15 | 127189c7ac65b |
hex | 8976ba8f83d3 |
151143029113811 has 16 divisors (see below), whose sum is σ = 175195421913600. Its totient is φ = 127706345141760.
The previous prime is 151143029113801. The next prime is 151143029113841. The reversal of 151143029113811 is 118311920341151.
It is not a de Polignac number, because 151143029113811 - 214 = 151143029097427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (151143029113801) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20845361 + ... + 27144338.
It is an arithmetic number, because the mean of its divisors is an integer number (10949713869600).
Almost surely, 2151143029113811 is an apocalyptic number.
151143029113811 is a deficient number, since it is larger than the sum of its proper divisors (24052392799789).
151143029113811 is an equidigital number, since it uses as much as digits as its factorization.
151143029113811 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47996114.
The product of its (nonzero) digits is 25920, while the sum is 41.
Adding to 151143029113811 its reverse (118311920341151), we get a palindrome (269454949454962).
The spelling of 151143029113811 in words is "one hundred fifty-one trillion, one hundred forty-three billion, twenty-nine million, one hundred thirteen thousand, eight hundred eleven".
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