Base | Representation |
---|---|
bin | 1101110000000111010101… |
… | …0000011111101001010001 |
3 | 1222112111000100222000221201 |
4 | 3130001311100133221101 |
5 | 3440212234021440423 |
6 | 52054051542151201 |
7 | 3120254641416301 |
oct | 334016520375121 |
9 | 58474010860851 |
10 | 15120252140113 |
11 | 48aa51017025a |
12 | 18424a5a22501 |
13 | 858aab718683 |
14 | 3a3b774d3601 |
15 | 1b34a48232ad |
hex | dc07541fa51 |
15120252140113 has 8 divisors (see below), whose sum is σ = 15205470698880. Its totient is φ = 15035041891440.
The previous prime is 15120252140111. The next prime is 15120252140153. The reversal of 15120252140113 is 31104125202151.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 15120252140113 - 21 = 15120252140111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15120252140111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1589931 + ... + 5724367.
It is an arithmetic number, because the mean of its divisors is an integer number (1900683837360).
Almost surely, 215120252140113 is an apocalyptic number.
It is an amenable number.
15120252140113 is a deficient number, since it is larger than the sum of its proper divisors (85218558767).
15120252140113 is a wasteful number, since it uses less digits than its factorization.
15120252140113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4155047.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 15120252140113 its reverse (31104125202151), we get a palindrome (46224377342264).
The spelling of 15120252140113 in words is "fifteen trillion, one hundred twenty billion, two hundred fifty-two million, one hundred forty thousand, one hundred thirteen".
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