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15121002243 = 35040334081
BaseRepresentation
bin11100001010100100…
…00010111100000011
31110000210211111120010
432011102002330003
5221431434032433
610540235320003
71043466253434
oct160522027403
943023744503
1015121002243
11645a458876
122b1bbb0003
13156c934209
14a3632148b
155d7766e63
hex385482f03

15121002243 has 4 divisors (see below), whose sum is σ = 20161336328. Its totient is φ = 10080668160.

The previous prime is 15121002233. The next prime is 15121002283. The reversal of 15121002243 is 34220012151.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 15121002243 - 26 = 15121002179 is a prime.

It is a super-3 number, since 3×151210022433 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15121002203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2520167038 + ... + 2520167043.

It is an arithmetic number, because the mean of its divisors is an integer number (5040334082).

Almost surely, 215121002243 is an apocalyptic number.

15121002243 is a deficient number, since it is larger than the sum of its proper divisors (5040334085).

15121002243 is an equidigital number, since it uses as much as digits as its factorization.

15121002243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5040334084.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 15121002243 its reverse (34220012151), we get a palindrome (49341014394).

The spelling of 15121002243 in words is "fifteen billion, one hundred twenty-one million, two thousand, two hundred forty-three".

Divisors: 1 3 5040334081 15121002243