Base | Representation |
---|---|
bin | 1101110000010110100001… |
… | …0101110111100000001011 |
3 | 1222112212112120221201022020 |
4 | 3130011220111313200023 |
5 | 3440244112041141133 |
6 | 52100004345455523 |
7 | 3120461002231026 |
oct | 334055025674013 |
9 | 58485476851266 |
10 | 15124330412043 |
11 | 4901213255326 |
12 | 18432437a15a3 |
13 | 8592ab613a28 |
14 | 3a4042dc01bd |
15 | 1b36428aa0b3 |
hex | dc16857780b |
15124330412043 has 4 divisors (see below), whose sum is σ = 20165773882728. Its totient is φ = 10082886941360.
The previous prime is 15124330412041. The next prime is 15124330412053. The reversal of 15124330412043 is 34021403342151.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 15124330412043 - 21 = 15124330412041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15124330411995 and 15124330412013.
It is not an unprimeable number, because it can be changed into a prime (15124330412041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2520721735338 + ... + 2520721735343.
It is an arithmetic number, because the mean of its divisors is an integer number (5041443470682).
Almost surely, 215124330412043 is an apocalyptic number.
15124330412043 is a deficient number, since it is larger than the sum of its proper divisors (5041443470685).
15124330412043 is an equidigital number, since it uses as much as digits as its factorization.
15124330412043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5041443470684.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 15124330412043 its reverse (34021403342151), we get a palindrome (49145733754194).
The spelling of 15124330412043 in words is "fifteen trillion, one hundred twenty-four billion, three hundred thirty million, four hundred twelve thousand, forty-three".
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