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15129986889601 = 29983504618847
BaseRepresentation
bin1101110000101011100101…
…1111100111011110000001
31222120102010210121112210001
43130022321133213132001
53440342203120431401
652102341531440001
73121051115421163
oct334127137473601
958512123545701
1015129986889601
114903656185671
121844361bb6001
138599a0483a7c
143a441c32a933
151b3874288601
hexdc2b97e7781

15129986889601 has 4 divisors (see below), whose sum is σ = 15130491538432. Its totient is φ = 15129482240772.

The previous prime is 15129986889581. The next prime is 15129986889613. The reversal of 15129986889601 is 10698868992151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15129986889601 - 27 = 15129986889473 is a prime.

It is a super-3 number, since 3×151299868896013 (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15129986889301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252279441 + ... + 252339406.

It is an arithmetic number, because the mean of its divisors is an integer number (3782622884608).

Almost surely, 215129986889601 is an apocalyptic number.

It is an amenable number.

15129986889601 is a deficient number, since it is larger than the sum of its proper divisors (504648831).

15129986889601 is an equidigital number, since it uses as much as digits as its factorization.

15129986889601 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 504648830.

The product of its (nonzero) digits is 134369280, while the sum is 73.

The spelling of 15129986889601 in words is "fifteen trillion, one hundred twenty-nine billion, nine hundred eighty-six million, eight hundred eighty-nine thousand, six hundred one".

Divisors: 1 29983 504618847 15129986889601