Base | Representation |
---|---|
bin | 1000110011101000110… |
… | …0111011011111111011 |
3 | 112110112101020210010122 |
4 | 2030322030323133323 |
5 | 4434330340321243 |
6 | 153301215003455 |
7 | 13634235346232 |
oct | 2147214733773 |
9 | 473471223118 |
10 | 151300323323 |
11 | 591910a7326 |
12 | 253a620958b |
13 | 11362a9b646 |
14 | 7474357b19 |
15 | 3e07d35668 |
hex | 233a33b7fb |
151300323323 has 4 divisors (see below), whose sum is σ = 160200342360. Its totient is φ = 142400304288.
The previous prime is 151300323301. The next prime is 151300323329. The reversal of 151300323323 is 323323003151.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 151300323323 - 224 = 151283546107 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 151300323292 and 151300323301.
It is not an unprimeable number, because it can be changed into a prime (151300323329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4450009493 + ... + 4450009526.
It is an arithmetic number, because the mean of its divisors is an integer number (40050085590).
Almost surely, 2151300323323 is an apocalyptic number.
151300323323 is a deficient number, since it is larger than the sum of its proper divisors (8900019037).
151300323323 is an equidigital number, since it uses as much as digits as its factorization.
151300323323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8900019036.
The product of its (nonzero) digits is 4860, while the sum is 26.
Adding to 151300323323 its reverse (323323003151), we get a palindrome (474623326474).
The spelling of 151300323323 in words is "one hundred fifty-one billion, three hundred million, three hundred twenty-three thousand, three hundred twenty-three".
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