15130041 has 4 divisors (see below), whose sum is σ = 20173392. Its totient is φ = 10086692.

The previous prime is 15130039. The next prime is 15130043. The reversal of 15130041 is 14003151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (15130039) and next prime (15130043).

It is a cyclic number.

It is not a de Polignac number, because 15130041 - 2¹ = 15130039 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 15130041.

It is not an unprimeable number, because it can be changed into a prime (15130043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2521671 + ... + 2521676.

It is an arithmetic number, because the mean of its divisors is an integer number (5043348).

Almost surely, 2^15130041 is an apocalyptic number.

It is an amenable number.

15130041 is a deficient number, since it is larger than the sum of its proper divisors (5043351).

15130041 is an equidigital number, since it uses as much as digits as its factorization.

15130041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5043350.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 15130041 is about 3889.7353380404. The cubic root of 15130041 is about 247.3318437408.

Adding to 15130041 its reverse (14003151), we get a palindrome (29133192).

The spelling of 15130041 in words is "fifteen million, one hundred thirty thousand, forty-one".