Base | Representation |
---|---|
bin | 11100001011111100… |
… | …00111010010100001 |
3 | 1110001121120102010211 |
4 | 32011332013102201 |
5 | 221442413220101 |
6 | 10541331054121 |
7 | 1043666406256 |
oct | 160576072241 |
9 | 43047512124 |
10 | 15132554401 |
11 | 6465a29108 |
12 | 2b23a41341 |
13 | 157214a403 |
14 | a37a8b42d |
15 | 5d8799c51 |
hex | 385f874a1 |
15132554401 has 4 divisors (see below), whose sum is σ = 15159433392. Its totient is φ = 15105675412.
The previous prime is 15132554387. The next prime is 15132554441. The reversal of 15132554401 is 10445523151.
15132554401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 15132554401 - 219 = 15132030113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15132554441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13438651 + ... + 13439776.
It is an arithmetic number, because the mean of its divisors is an integer number (3789858348).
Almost surely, 215132554401 is an apocalyptic number.
It is an amenable number.
15132554401 is a deficient number, since it is larger than the sum of its proper divisors (26878991).
15132554401 is an equidigital number, since it uses as much as digits as its factorization.
15132554401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26878990.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 15132554401 in words is "fifteen billion, one hundred thirty-two million, five hundred fifty-four thousand, four hundred one".
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