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151332101536153 = 1225312350616301
BaseRepresentation
bin100010011010001011000000…
…001001111011100110011001
3201211211012121100112020200011
4202122023000021323212121
5124313411120443124103
61253505001355041521
743606245360036346
oct4232130011734631
9654735540466604
10151332101536153
114424564710871a
1214b812127402a1
13665972c533555
1429527271797cd
1512767666ead6d
hex89a2c027b999

151332101536153 has 4 divisors (see below), whose sum is σ = 151344452164708. Its totient is φ = 151319750907600.

The previous prime is 151332101536151. The next prime is 151332101536193. The reversal of 151332101536153 is 351635101233151.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74722746869824 + 76609354666329 = 8644232^2 + 8752677^2 .

It is a cyclic number.

It is not a de Polignac number, because 151332101536153 - 21 = 151332101536151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (151332101536151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6175295898 + ... + 6175320403.

It is an arithmetic number, because the mean of its divisors is an integer number (37836113041177).

Almost surely, 2151332101536153 is an apocalyptic number.

It is an amenable number.

151332101536153 is a deficient number, since it is larger than the sum of its proper divisors (12350628555).

151332101536153 is a wasteful number, since it uses less digits than its factorization.

151332101536153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12350628554.

The product of its (nonzero) digits is 121500, while the sum is 40.

The spelling of 151332101536153 in words is "one hundred fifty-one trillion, three hundred thirty-two billion, one hundred one million, five hundred thirty-six thousand, one hundred fifty-three".

Divisors: 1 12253 12350616301 151332101536153