Base | Representation |
---|---|
bin | 1101110000110111101011… |
… | …0011010011111011011011 |
3 | 1222120201111211012102111220 |
4 | 3130031322303103323123 |
5 | 3440420323343231011 |
6 | 52104035424023123 |
7 | 3121224356032236 |
oct | 334157263237333 |
9 | 58521454172456 |
10 | 15133230055131 |
11 | 4904a6a930961 |
12 | 1844b08161aa3 |
13 | 85a099356c26 |
14 | 3a4648d5041d |
15 | 1b39b3d61506 |
hex | dc37acd3edb |
15133230055131 has 16 divisors (see below), whose sum is σ = 21366987675264. Its totient is φ = 9494281102464.
The previous prime is 15133230055109. The next prime is 15133230055133. The reversal of 15133230055131 is 13155003233151.
It is not a de Polignac number, because 15133230055131 - 221 = 15133227957979 is a prime.
It is a super-2 number, since 2×151332300551312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15133230055092 and 15133230055101.
It is not an unprimeable number, because it can be changed into a prime (15133230055133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16404961 + ... + 17302866.
It is an arithmetic number, because the mean of its divisors is an integer number (1335436729704).
Almost surely, 215133230055131 is an apocalyptic number.
15133230055131 is a deficient number, since it is larger than the sum of its proper divisors (6233757620133).
15133230055131 is a wasteful number, since it uses less digits than its factorization.
15133230055131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33716650.
The product of its (nonzero) digits is 20250, while the sum is 33.
Adding to 15133230055131 its reverse (13155003233151), we get a palindrome (28288233288282).
The spelling of 15133230055131 in words is "fifteen trillion, one hundred thirty-three billion, two hundred thirty million, fifty-five thousand, one hundred thirty-one".
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