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1513401650707 = 13046911599703
BaseRepresentation
bin10110000001011101110…
…001001000111000010011
312100200100120012112101011
4112001131301020320103
5144243421310310312
63115125213351351
7214224334531342
oct26013561107023
95320316175334
101513401650707
11533914860981
12205383198557
13ac936a8703b
145336b4a9b59
1529578bd8da7
hex1605dc48e13

1513401650707 has 4 divisors (see below), whose sum is σ = 1513413380880. Its totient is φ = 1513389920536.

The previous prime is 1513401650699. The next prime is 1513401650749. The reversal of 1513401650707 is 7070561043151.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1513401650707 - 23 = 1513401650699 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1513401650707.

It is not an unprimeable number, because it can be changed into a prime (1513401650777) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5669383 + ... + 5930320.

It is an arithmetic number, because the mean of its divisors is an integer number (378353345220).

Almost surely, 21513401650707 is an apocalyptic number.

1513401650707 is a deficient number, since it is larger than the sum of its proper divisors (11730173).

1513401650707 is a wasteful number, since it uses less digits than its factorization.

1513401650707 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11730172.

The product of its (nonzero) digits is 88200, while the sum is 40.

Adding to 1513401650707 its reverse (7070561043151), we get a palindrome (8583962693858).

The spelling of 1513401650707 in words is "one trillion, five hundred thirteen billion, four hundred one million, six hundred fifty thousand, seven hundred seven".

Divisors: 1 130469 11599703 1513401650707