Base | Representation |
---|---|
bin | 11100001100001001… |
… | …10100011100001001 |
3 | 1110001201212201101112 |
4 | 32012010310130021 |
5 | 221443340442301 |
6 | 10541432500105 |
7 | 1044020350121 |
oct | 160604643411 |
9 | 43051781345 |
10 | 15134312201 |
11 | 6466a19838 |
12 | 2b2454a635 |
13 | 1572614528 |
14 | a37dc7c81 |
15 | 5d89e59bb |
hex | 386134709 |
15134312201 has 4 divisors (see below), whose sum is σ = 15230709252. Its totient is φ = 15037915152.
The previous prime is 15134312191. The next prime is 15134312239. The reversal of 15134312201 is 10221343151.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10221343151 = 19 ⋅537965429.
It can be written as a sum of positive squares in 2 ways, for example, as 10601791225 + 4532520976 = 102965^2 + 67324^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15134312201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15134302201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48198290 + ... + 48198603.
It is an arithmetic number, because the mean of its divisors is an integer number (3807677313).
Almost surely, 215134312201 is an apocalyptic number.
It is an amenable number.
15134312201 is a deficient number, since it is larger than the sum of its proper divisors (96397051).
15134312201 is an equidigital number, since it uses as much as digits as its factorization.
15134312201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96397050.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 15134312201 its reverse (10221343151), we get a palindrome (25355655352).
The spelling of 15134312201 in words is "fifteen billion, one hundred thirty-four million, three hundred twelve thousand, two hundred one".
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