Base | Representation |
---|---|
bin | 100010011010010101100110… |
… | …001100110110001000100011 |
3 | 201211212021222010221112001010 |
4 | 202122111212030312020203 |
5 | 124314102420134041033 |
6 | 1253514122244112003 |
7 | 43610130311034504 |
oct | 4232254614661043 |
9 | 654767863845033 |
10 | 151343477252643 |
11 | 4424a454435905 |
12 | 14b83468395603 |
13 | 665a823249440 |
14 | 29530c5cccbab |
15 | 1276bd0253863 |
hex | 89a566336223 |
151343477252643 has 8 divisors (see below), whose sum is σ = 217313710926928. Its totient is φ = 93134447540064.
The previous prime is 151343477252581. The next prime is 151343477252647. The reversal of 151343477252643 is 346252774343151.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 151343477252643 - 29 = 151343477252131 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (151343477252647) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1940300990380 + ... + 1940300990457.
It is an arithmetic number, because the mean of its divisors is an integer number (27164213865866).
Almost surely, 2151343477252643 is an apocalyptic number.
151343477252643 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
151343477252643 is a deficient number, since it is larger than the sum of its proper divisors (65970233674285).
151343477252643 is a wasteful number, since it uses less digits than its factorization.
151343477252643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3880601980853.
The product of its digits is 50803200, while the sum is 57.
The spelling of 151343477252643 in words is "one hundred fifty-one trillion, three hundred forty-three billion, four hundred seventy-seven million, two hundred fifty-two thousand, six hundred forty-three".
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