Base | Representation |
---|---|
bin | 11100001101001110… |
… | …10000110100001001 |
3 | 1110002100212110000101 |
4 | 32012213100310021 |
5 | 222003143410241 |
6 | 10542354205401 |
7 | 1044160164103 |
oct | 160647206411 |
9 | 43070773011 |
10 | 15143341321 |
11 | 6471026519 |
12 | 2b27583861 |
13 | 15744561c4 |
14 | a39298573 |
15 | 5d96cae31 |
hex | 3869d0d09 |
15143341321 has 4 divisors (see below), whose sum is σ = 15155724672. Its totient is φ = 15130957972.
The previous prime is 15143341309. The next prime is 15143341327. The reversal of 15143341321 is 12314334151.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 15143341321 - 215 = 15143308553 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 15143341321.
It is not an unprimeable number, because it can be changed into a prime (15143341327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6189841 + ... + 6192286.
It is an arithmetic number, because the mean of its divisors is an integer number (3788931168).
Almost surely, 215143341321 is an apocalyptic number.
It is an amenable number.
15143341321 is a deficient number, since it is larger than the sum of its proper divisors (12383351).
15143341321 is a wasteful number, since it uses less digits than its factorization.
15143341321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12383350.
The product of its digits is 4320, while the sum is 28.
Adding to 15143341321 its reverse (12314334151), we get a palindrome (27457675472).
The spelling of 15143341321 in words is "fifteen billion, one hundred forty-three million, three hundred forty-one thousand, three hundred twenty-one".
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