1520231134041 has 12 divisors (see below), whose sum is σ = 2196135349668. Its totient is φ = 1013373914784.

The previous prime is 1520231133973. The next prime is 1520231134063. The reversal of 1520231134041 is 1404311320251.

1520231134041 is a `hidden beast` number, since 1 + 5 + 2 + 0 + 2 + 311 + 340 + 4 + 1 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 671409804816 + 848821329225 = 819396^2 + 921315^2 .

It is not a de Polignac number, because 1520231134041 - 2⁷ = 1520231133913 is a prime.

It is a super-2 number, since 2×1520231134041² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1520231133996 and 1520231134014.

It is not an unprimeable number, because it can be changed into a prime (1520231134441) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9374130 + ... + 9534923.

It is an arithmetic number, because the mean of its divisors is an integer number (183011279139).

Almost surely, 2^{1520231134041} is an apocalyptic number.

It is an amenable number.

1520231134041 is a deficient number, since it is larger than the sum of its proper divisors (675904215627).

1520231134041 is a wasteful number, since it uses less digits than its factorization.

1520231134041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18917992 (or 18917989 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 1520231134041 its reverse (1404311320251), we get a palindrome (2924542454292).

The spelling of 1520231134041 in words is "one trillion, five hundred twenty billion, two hundred thirty-one million, one hundred thirty-four thousand, forty-one".