152425300049 has 4 divisors (see below), whose sum is σ = 166282145520. Its totient is φ = 138568454580.

The previous prime is 152425300043. The next prime is 152425300061. The reversal of 152425300049 is 940003524251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-152425300049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 152425299991 and 152425300018.

It is not an unprimeable number, because it can be changed into a prime (152425300043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6928422719 + ... + 6928422740.

It is an arithmetic number, because the mean of its divisors is an integer number (41570536380).

Almost surely, 2^152425300049 is an apocalyptic number.

It is an amenable number.

152425300049 is a deficient number, since it is larger than the sum of its proper divisors (13856845471).

152425300049 is a wasteful number, since it uses less digits than its factorization.

152425300049 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13856845470.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 152425300049 in words is "one hundred fifty-two billion, four hundred twenty-five million, three hundred thousand, forty-nine".