15243324113 has 4 divisors (see below), whose sum is σ = 15615112548. Its totient is φ = 14871535680.

The previous prime is 15243324079. The next prime is 15243324163. The reversal of 15243324113 is 31142334251.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1654292929 + 13589031184 = 40673^2 + 116572^2 .

It is a cyclic number.

It is not a de Polignac number, because 15243324113 - 2¹⁰ = 15243323089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15243324163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185894156 + ... + 185894237.

It is an arithmetic number, because the mean of its divisors is an integer number (3903778137).

Almost surely, 2^15243324113 is an apocalyptic number.

It is an amenable number.

15243324113 is a deficient number, since it is larger than the sum of its proper divisors (371788435).

15243324113 is an equidigital number, since it uses as much as digits as its factorization.

15243324113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 371788434.

The product of its digits is 8640, while the sum is 29.

Adding to 15243324113 its reverse (31142334251), we get a palindrome (46385658364).

The spelling of 15243324113 in words is "fifteen billion, two hundred forty-three million, three hundred twenty-four thousand, one hundred thirteen".