Base | Representation |
---|---|
bin | 1000111000001001001… |
… | …1111101000000000011 |
3 | 112120122200201000201102 |
4 | 2032002103331000003 |
5 | 4444320042432120 |
6 | 154021233125015 |
7 | 14006225444063 |
oct | 2160223750003 |
9 | 476580630642 |
10 | 152510124035 |
11 | 59751a97525 |
12 | 256833b976b |
13 | 114c6614a59 |
14 | 754acb93a3 |
15 | 3e79159d75 |
hex | 23824fd003 |
152510124035 has 4 divisors (see below), whose sum is σ = 183012148848. Its totient is φ = 122008099224.
The previous prime is 152510124031. The next prime is 152510124047. The reversal of 152510124035 is 530421015251.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530421015251 = 152407 ⋅3480293.
It is a cyclic number.
It is not a de Polignac number, because 152510124035 - 22 = 152510124031 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 152510123989 and 152510124007.
It is not an unprimeable number, because it can be changed into a prime (152510124031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15251012399 + ... + 15251012408.
It is an arithmetic number, because the mean of its divisors is an integer number (45753037212).
Almost surely, 2152510124035 is an apocalyptic number.
152510124035 is a deficient number, since it is larger than the sum of its proper divisors (30502024813).
152510124035 is an equidigital number, since it uses as much as digits as its factorization.
152510124035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30502024812.
The product of its (nonzero) digits is 6000, while the sum is 29.
Adding to 152510124035 its reverse (530421015251), we get a palindrome (682931139286).
The spelling of 152510124035 in words is "one hundred fifty-two billion, five hundred ten million, one hundred twenty-four thousand, thirty-five".
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