Base | Representation |
---|---|
bin | 1101110111111101110000… |
… | …0110011100001111000011 |
3 | 2000000101010122112122010111 |
4 | 3131333130012130033003 |
5 | 3444414442103403011 |
6 | 52240034525412151 |
7 | 3133101063425650 |
oct | 335773406341703 |
9 | 60011118478114 |
10 | 15255121544131 |
11 | 495172a458727 |
12 | 186466540a057 |
13 | 868723384c51 |
14 | 3aa4cd586c27 |
15 | 1b6c49de3121 |
hex | ddfdc19c3c3 |
15255121544131 has 8 divisors (see below), whose sum is σ = 17439905447264. Its totient is φ = 13071707847360.
The previous prime is 15255121544053. The next prime is 15255121544137. The reversal of 15255121544131 is 13144512155251.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 15255121544131 - 213 = 15255121535939 is a prime.
It is a super-2 number, since 2×152551215441312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15255121544137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 342527730 + ... + 342572263.
It is an arithmetic number, because the mean of its divisors is an integer number (2179988180908).
Almost surely, 215255121544131 is an apocalyptic number.
15255121544131 is a deficient number, since it is larger than the sum of its proper divisors (2184783903133).
15255121544131 is an equidigital number, since it uses as much as digits as its factorization.
15255121544131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 685103181.
The product of its digits is 120000, while the sum is 40.
Adding to 15255121544131 its reverse (13144512155251), we get a palindrome (28399633699382).
The spelling of 15255121544131 in words is "fifteen trillion, two hundred fifty-five billion, one hundred twenty-one million, five hundred forty-four thousand, one hundred thirty-one".
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