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152552334313 = 198029070227
BaseRepresentation
bin1000111000010011010…
…0111110001111101001
3112120202122010112100001
42032010310332033221
54444411344144223
6154025341543001
714010250306111
oct2160464761751
9476678115301
10152552334313
11597738a7755
1225695574a61
13115022a3652
147552746041
153e7cbe69ad
hex2384d3e3e9

152552334313 has 4 divisors (see below), whose sum is σ = 160581404560. Its totient is φ = 144523264068.

The previous prime is 152552334247. The next prime is 152552334349. The reversal of 152552334313 is 313433255251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 152552334313 - 217 = 152552203241 is a prime.

It is a super-3 number, since 3×1525523343133 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (152552334413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4014535095 + ... + 4014535132.

It is an arithmetic number, because the mean of its divisors is an integer number (40145351140).

Almost surely, 2152552334313 is an apocalyptic number.

It is an amenable number.

152552334313 is a deficient number, since it is larger than the sum of its proper divisors (8029070247).

152552334313 is an equidigital number, since it uses as much as digits as its factorization.

152552334313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8029070246.

The product of its digits is 162000, while the sum is 37.

Adding to 152552334313 its reverse (313433255251), we get a palindrome (465985589564).

The spelling of 152552334313 in words is "one hundred fifty-two billion, five hundred fifty-two million, three hundred thirty-four thousand, three hundred thirteen".

Divisors: 1 19 8029070227 152552334313