Base | Representation |
---|---|
bin | 1000111000010011110… |
… | …0001111110000001011 |
3 | 112120202202201101212101 |
4 | 2032010330033300023 |
5 | 4444412341203120 |
6 | 154025450454231 |
7 | 14010302440060 |
oct | 2160474176013 |
9 | 476682641771 |
10 | 152554241035 |
11 | 5977498a259 |
12 | 25696134377 |
13 | 115027c04a1 |
14 | 7552ac0c67 |
15 | 3e7ce7190a |
hex | 2384f0fc0b |
152554241035 has 16 divisors (see below), whose sum is σ = 209224071936. Its totient is φ = 104605208928.
The previous prime is 152554241033. The next prime is 152554241041. The reversal of 152554241035 is 530142455251.
It is a cyclic number.
It is not a de Polignac number, because 152554241035 - 21 = 152554241033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 152554240985 and 152554241003.
It is not an unprimeable number, because it can be changed into a prime (152554241033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1515132 + ... + 1612678.
It is an arithmetic number, because the mean of its divisors is an integer number (13076504496).
Almost surely, 2152554241035 is an apocalyptic number.
152554241035 is a deficient number, since it is larger than the sum of its proper divisors (56669830901).
152554241035 is an equidigital number, since it uses as much as digits as its factorization.
152554241035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142242.
The product of its (nonzero) digits is 120000, while the sum is 37.
Adding to 152554241035 its reverse (530142455251), we get a palindrome (682696696286).
The spelling of 152554241035 in words is "one hundred fifty-two billion, five hundred fifty-four million, two hundred forty-one thousand, thirty-five".
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