Base | Representation |
---|---|
bin | 1000111000010011110… |
… | …0100101101110101011 |
3 | 112120202202212222100022 |
4 | 2032010330211232223 |
5 | 4444412402043201 |
6 | 154025452431055 |
7 | 14010303263363 |
oct | 2160474455653 |
9 | 476682788308 |
10 | 152554331051 |
11 | 59774a40951 |
12 | 2569617848b |
13 | 11502822455 |
14 | 7552b059a3 |
15 | 3e7ce8d41b |
hex | 2384f25bab |
152554331051 has 4 divisors (see below), whose sum is σ = 152555147112. Its totient is φ = 152553514992.
The previous prime is 152554331029. The next prime is 152554331089. The reversal of 152554331051 is 150133455251.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 150133455251 = 13 ⋅11548727327.
It is a cyclic number.
It is not a de Polignac number, because 152554331051 - 26 = 152554330987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (152554331011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26951 + ... + 553023.
It is an arithmetic number, because the mean of its divisors is an integer number (38138786778).
Almost surely, 2152554331051 is an apocalyptic number.
152554331051 is a deficient number, since it is larger than the sum of its proper divisors (816061).
152554331051 is an equidigital number, since it uses as much as digits as its factorization.
152554331051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 816060.
The product of its (nonzero) digits is 45000, while the sum is 35.
The spelling of 152554331051 in words is "one hundred fifty-two billion, five hundred fifty-four million, three hundred thirty-one thousand, fifty-one".
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