Base | Representation |
---|---|
bin | 100010101101101001101001… |
… | …100001111011110100001011 |
3 | 202000120011201001022110120201 |
4 | 202231221221201323310023 |
5 | 130002324022032211201 |
6 | 1300411535150233031 |
7 | 44105043503231161 |
oct | 4255515141736413 |
9 | 660504631273521 |
10 | 152670678007051 |
11 | 447112a8689416 |
12 | 151587251b5777 |
13 | 6725a247b3c19 |
14 | 299b42bc17231 |
15 | 129b4ac166801 |
hex | 8ada6987bd0b |
152670678007051 has 4 divisors (see below), whose sum is σ = 155258316617400. Its totient is φ = 150083039396704.
The previous prime is 152670678007039. The next prime is 152670678007079. The reversal of 152670678007051 is 150700876076251.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 152670678007051 - 27 = 152670678006923 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 152670678006983 and 152670678007001.
It is not an unprimeable number, because it can be changed into a prime (152670678037051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1293819305086 + ... + 1293819305203.
It is an arithmetic number, because the mean of its divisors is an integer number (38814579154350).
Almost surely, 2152670678007051 is an apocalyptic number.
152670678007051 is a deficient number, since it is larger than the sum of its proper divisors (2587638610349).
152670678007051 is an equidigital number, since it uses as much as digits as its factorization.
152670678007051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2587638610348.
The product of its (nonzero) digits is 4939200, while the sum is 55.
The spelling of 152670678007051 in words is "one hundred fifty-two trillion, six hundred seventy billion, six hundred seventy-eight million, seven thousand, fifty-one".
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