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15300050041 = 23665219567
BaseRepresentation
bin11100011111111010…
…00011110001111001
31110111021202001222001
432033331003301321
5222313303100131
611010113101001
71051102164613
oct161775036171
943437661861
1015300050041
116541530061
122b6bb57761
13159aa63863
14a5200bdb3
155e8333261
hex38ff43c79

15300050041 has 4 divisors (see below), whose sum is σ = 15965269632. Its totient is φ = 14634830452.

The previous prime is 15300050039. The next prime is 15300050053. The reversal of 15300050041 is 14005000351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14005000351 = 37378513523.

It is a cyclic number.

It is not a de Polignac number, because 15300050041 - 21 = 15300050039 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15300050011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 332609761 + ... + 332609806.

It is an arithmetic number, because the mean of its divisors is an integer number (3991317408).

Almost surely, 215300050041 is an apocalyptic number.

It is an amenable number.

15300050041 is a deficient number, since it is larger than the sum of its proper divisors (665219591).

15300050041 is an equidigital number, since it uses as much as digits as its factorization.

15300050041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 665219590.

The product of its (nonzero) digits is 300, while the sum is 19.

Adding to 15300050041 its reverse (14005000351), we get a palindrome (29305050392).

The spelling of 15300050041 in words is "fifteen billion, three hundred million, fifty thousand, forty-one".

Divisors: 1 23 665219567 15300050041