Base | Representation |
---|---|
bin | 1000111010011000010… |
… | …1010001100110101011 |
3 | 112122012111221220001211 |
4 | 2032212011101212223 |
5 | 10002032211143133 |
6 | 154200552053551 |
7 | 14030133463063 |
oct | 2164605214653 |
9 | 478174856054 |
10 | 153110256043 |
11 | 59a2a825598 |
12 | 258103942b7 |
13 | 11590a58754 |
14 | 75a68983a3 |
15 | 3eb1ba1bcd |
hex | 23a61519ab |
153110256043 has 4 divisors (see below), whose sum is σ = 153362497600. Its totient is φ = 152858014488.
The previous prime is 153110255993. The next prime is 153110256071. The reversal of 153110256043 is 340652011351.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 153110256043 - 217 = 153110124971 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 153110255996 and 153110256014.
It is not an unprimeable number, because it can be changed into a prime (153110256643) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126119868 + ... + 126121081.
It is an arithmetic number, because the mean of its divisors is an integer number (38340624400).
Almost surely, 2153110256043 is an apocalyptic number.
153110256043 is a deficient number, since it is larger than the sum of its proper divisors (252241557).
153110256043 is an equidigital number, since it uses as much as digits as its factorization.
153110256043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252241556.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 153110256043 its reverse (340652011351), we get a palindrome (493762267394).
The spelling of 153110256043 in words is "one hundred fifty-three billion, one hundred ten million, two hundred fifty-six thousand, forty-three".
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