Base | Representation |
---|---|
bin | 100010110100001101000010… |
… | …111011101001011100011011 |
3 | 202002011020001220100122222211 |
4 | 202310031002323221130123 |
5 | 130032213303003032303 |
6 | 1301354452304255551 |
7 | 44152425113103214 |
oct | 4264150273513433 |
9 | 662136056318884 |
10 | 153121002002203 |
11 | 44875285857154 |
12 | 1520ba619115b7 |
13 | 6759330041791 |
14 | 29b514b76840b |
15 | 12a8066aa366d |
hex | 8b4342ee971b |
153121002002203 has 16 divisors (see below), whose sum is σ = 164536711073856. Its totient is φ = 142123040864640.
The previous prime is 153121002002173. The next prime is 153121002002321. The reversal of 153121002002203 is 302200200121351.
153121002002203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 153121002002203 - 213 = 153121001994011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (153121002012203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 240876508 + ... + 241511353.
It is an arithmetic number, because the mean of its divisors is an integer number (10283544442116).
Almost surely, 2153121002002203 is an apocalyptic number.
153121002002203 is a deficient number, since it is larger than the sum of its proper divisors (11415709071653).
153121002002203 is a wasteful number, since it uses less digits than its factorization.
153121002002203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 482388294.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 153121002002203 its reverse (302200200121351), we get a palindrome (455321202123554).
The spelling of 153121002002203 in words is "one hundred fifty-three trillion, one hundred twenty-one billion, two million, two thousand, two hundred three".
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