Base | Representation |
---|---|
bin | 1000111010011010111… |
… | …1011101011010000011 |
3 | 112122020021202201022220 |
4 | 2032212233131122003 |
5 | 10002043024030220 |
6 | 154202025102123 |
7 | 14030326461225 |
oct | 2164657353203 |
9 | 478207681286 |
10 | 153121314435 |
11 | 59a35a98961 |
12 | 25814027943 |
13 | 1159312ac8b |
14 | 75a8136415 |
15 | 3eb2b38540 |
hex | 23a6bdd683 |
153121314435 has 8 divisors (see below), whose sum is σ = 244994103120. Its totient is φ = 81664701024.
The previous prime is 153121314413. The next prime is 153121314481. The reversal of 153121314435 is 534413121351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 153121314435 - 25 = 153121314403 is a prime.
It is a super-2 number, since 2×1531213144352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 153121314396 and 153121314405.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5104043800 + ... + 5104043829.
It is an arithmetic number, because the mean of its divisors is an integer number (30624262890).
Almost surely, 2153121314435 is an apocalyptic number.
153121314435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
153121314435 is a deficient number, since it is larger than the sum of its proper divisors (91872788685).
153121314435 is a wasteful number, since it uses less digits than its factorization.
153121314435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10208087637.
The product of its digits is 21600, while the sum is 33.
Adding to 153121314435 its reverse (534413121351), we get a palindrome (687534435786).
The spelling of 153121314435 in words is "one hundred fifty-three billion, one hundred twenty-one million, three hundred fourteen thousand, four hundred thirty-five".
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