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153123714339 = 351041238113
BaseRepresentation
bin1000111010011011100…
…0100111010100100011
3112122020110021122101020
42032212320213110203
510002044132324324
6154202152340523
714030356045101
oct2164670472443
9478213248336
10153123714339
1159a37387a52
12258149a4743
131159378b43b
1475a859cc71
153eb2e5e679
hex23a6e27523

153123714339 has 4 divisors (see below), whose sum is σ = 204164952456. Its totient is φ = 102082476224.

The previous prime is 153123714313. The next prime is 153123714361. The reversal of 153123714339 is 933417321351.

153123714339 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 153123714339 - 25 = 153123714307 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 153123714339.

It is not an unprimeable number, because it can be changed into a prime (153123714439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25520619054 + ... + 25520619059.

It is an arithmetic number, because the mean of its divisors is an integer number (51041238114).

Almost surely, 2153123714339 is an apocalyptic number.

153123714339 is a deficient number, since it is larger than the sum of its proper divisors (51041238117).

153123714339 is an equidigital number, since it uses as much as digits as its factorization.

153123714339 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51041238116.

The product of its digits is 204120, while the sum is 42.

The spelling of 153123714339 in words is "one hundred fifty-three billion, one hundred twenty-three million, seven hundred fourteen thousand, three hundred thirty-nine".

Divisors: 1 3 51041238113 153123714339