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15314551345 = 53062910269
BaseRepresentation
bin11100100001101000…
…11000001000110001
31110112022000211000101
432100310120020301
5222331011120340
611011351552401
71051336352512
oct162064301061
943468024011
1015314551345
116549735105
122b7498b701
1315a0a70202
14a53d04a09
155e9749c9a
hex390d18231

15314551345 has 4 divisors (see below), whose sum is σ = 18377461620. Its totient is φ = 12251641072.

The previous prime is 15314551313. The next prime is 15314551409. The reversal of 15314551345 is 54315541351.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54315541351 = 76497100999.

It can be written as a sum of positive squares in 2 ways, for example, as 10493748721 + 4820802624 = 102439^2 + 69432^2 .

It is a cyclic number.

It is not a de Polignac number, because 15314551345 - 25 = 15314551313 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1531455130 + ... + 1531455139.

It is an arithmetic number, because the mean of its divisors is an integer number (4594365405).

Almost surely, 215314551345 is an apocalyptic number.

It is an amenable number.

15314551345 is a deficient number, since it is larger than the sum of its proper divisors (3062910275).

15314551345 is an equidigital number, since it uses as much as digits as its factorization.

15314551345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3062910274.

The product of its digits is 90000, while the sum is 37.

The spelling of 15314551345 in words is "fifteen billion, three hundred fourteen million, five hundred fifty-one thousand, three hundred forty-five".

Divisors: 1 5 3062910269 15314551345