Base | Representation |
---|---|
bin | 100010110111010010100110… |
… | …010001011000000110110011 |
3 | 202002220111120220122002002000 |
4 | 202313102212101120012303 |
5 | 130044202213220241433 |
6 | 1302040132553025043 |
7 | 44203644463504125 |
oct | 4267224621300663 |
9 | 662814526562060 |
10 | 153333122040243 |
11 | 44947237007312 |
12 | 15244ba03b5183 |
13 | 67733363337a2 |
14 | 29c1511393215 |
15 | 12ad82e0aa113 |
hex | 8b74a64581b3 |
153333122040243 has 16 divisors (see below), whose sum is σ = 227164033920000. Its totient is φ = 102220347456360.
The previous prime is 153333122040229. The next prime is 153333122040257. The reversal of 153333122040243 is 342040221333351.
153333122040243 is a `hidden beast` number, since 1 + 5 + 333 + 312 + 2 + 0 + 4 + 0 + 2 + 4 + 3 = 666.
It is an interprime number because it is at equal distance from previous prime (153333122040229) and next prime (153333122040257).
It is not a de Polignac number, because 153333122040243 - 25 = 153333122040211 is a prime.
It is a super-2 number, since 2×1533331220402432 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 153333122040198 and 153333122040207.
It is not an unprimeable number, because it can be changed into a prime (153333122040443) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46541743 + ... + 49727256.
It is an arithmetic number, because the mean of its divisors is an integer number (14197752120000).
Almost surely, 2153333122040243 is an apocalyptic number.
153333122040243 is a deficient number, since it is larger than the sum of its proper divisors (73830911879757).
153333122040243 is an equidigital number, since it uses as much as digits as its factorization.
153333122040243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96327999 (or 96327993 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 36.
Adding to 153333122040243 its reverse (342040221333351), we get a palindrome (495373343373594).
The spelling of 153333122040243 in words is "one hundred fifty-three trillion, three hundred thirty-three billion, one hundred twenty-two million, forty thousand, two hundred forty-three".
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